Answer:
The answer is 8.5=(x-2.5)^2+(y-3)^2+(z-4.5)^2
Step-by-step explanation:
First we need to find diameter of the sphere. The distance point A and point B is:
d/2=r=2.92
radius of the sphere is 2.92 units
and the center of the sphere is:
C=((4+1)/2,(3+3)/2,(7+2)/2)
C=(2.5,3,4.5)
We can write the equation of the sphere as:
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds