All categories

3 years ago

How much would $500 invested at 5% interest compounded continuously be worth after 8 years?

Mathematics

1 answer:

alekssr [168]3 years ago

5 0

Answer:

Step-by-step explanation:

We will need to use the compound interest formula:

A = P(1 + r)ⁿ

A = final amount

P = Initial amount

r = rate

n = time applied

Our equation will then look like this

A = 500(1.05)⁸

A = 738.72772

You might be interested in

A car salesperson sells a car for $21,000. She receives a 5.25% commission on the sale of the car.

valkas [14]

She receives $1,102.50 for commission. All you need to do to solve this problem is multiply the amount given by the percentage as a decimal.

5 0

3 years ago

Read 2 more answers

great rapids white water rafting company rents for $125 per hour. Explain why the point (0,0) and (1,125) are on the graph of th

Artist 52 [7]

(0,0) represents the very beginning of the rental period: 0 time has elapsed, and thus there is no charge.

(1,125) represents this situation 1 hour after the rental has begun, and shows that the amount due at that point for the rental is

$125.

5 0

3 years ago

Read 2 more answers

Given numbers 2 ,5,11, 4.5, 1/10, V3 then

Black_prince [1.1K]

Answer:

a. pick two between 2,5 or 11, they are all primes.

b. it's 11 since

$11 {}^{2} = 121$

c. that's

$18 \times \frac{25}{100} = 4.5$

(or think about it as half the half of 18, so half of 9)

$\sqrt{3}$

Rest can be written as a fraction

3 0

3 years ago

Find the great is perfect square of 244

IgorLugansk [536]

I hope this helps you

244=4.61

2square roof 61

7 0

4 years ago

A certain type of thread is manufactured with a mean tensile strength of 78.3 kilograms and a standard deviation of 5.6 kilogram

azamat

Answer:

(a) The variance decreases.

(b) The variance increases.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the sample mean is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The standard deviation of sample mean is inversely proportional to the sample size, n.

So, if n increases then the standard deviation will decrease and vice-versa.

(a)

The sample size is increased from 64 to 196.

As mentioned above, if the sample size is increased then the standard deviation will decrease.

So, on increasing the value of n from 64 to 196, the standard deviation of the sample mean will decrease.

The standard deviation of the sample mean for n = 64 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{64}}=0.7$

The standard deviation of the sample mean for n = 196 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4$

The standard deviation of the sample mean decreased from 0.7 to 0.4 when n is increased from 64 to 196.

Hence, the variance also decreases.

(b)

If the sample size is decreased then the standard deviation will increase.

So, on decreasing the value of n from 784 to 49, the standard deviation of the sample mean will increase.

The standard deviation of the sample mean for n = 784 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{784}}=0.2$

The standard deviation of the sample mean for n = 49 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{49}}=0.8$

The standard deviation of the sample mean increased from 0.2 to 0.8 when n is decreased from 784 to 49.

Hence, the variance also increases.

6 0

3 years ago