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Andrei [34K]
3 years ago
11

How to solve this problem (x^n+y^n) divisible by (x+y)

Mathematics
1 answer:
Nuetrik [128]3 years ago
8 0

Use \\\\a^n + b^n = (a+b)(a^{n-1}b^0 - a^{n-2}b^1 + a^{n-3}b^2 - ... - a^1b^{n-2} + a^0b^{n-1}) \\--------------------------------\\\\\dfrac{x^n+y^n}{x+y}=\dfrac{(x+y)(x^{n-1}y^0-x^{n-2}y^1+x^{n-3}y^2-...-x^1y^{n-2}+x^0y^{n-1})}{x+y}\\\\=\boxed{x^{n-1}-x^{n-2}y+x^{n-3}y^2-...-xy^{n-2}+y^{n-1}}

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ipn [44]

Answer:

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Step-by-step explanation:

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Solve for y <br><br> 5y- 10x = 45
nasty-shy [4]

Answer:

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Step-by-step explanation:

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5y=45

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6 0
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What is the solution set of 4x = y and 2x^2− y = 0?
Alona [7]

Answer:{0,2}

Step-by-step explanation:

Substitute 4x in for the y

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