Answer:
0.01533036946190
Step-by-step explanation:
10÷652.3
0.01533036946190
Answer:
The third score must be larger than or equal to 72, and smaller than or equal 87
Step-by-step explanation:
Let's name "x" the third quiz score for which we need to find the values to get the desired average.
Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

This inequality tells us that the score in the third quiz must be larger than or equal to 72.
Now we study the second inequality to find the other restriction on "x":

This ine
quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.
Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:
This equation is in slope-intercept form; y = mx+b.
m is the slope and b is the y-intercept, so to find the slope you'd look at the coefficient of x.
In this equation, y = 3x+5, the coefficient of x is 3, so that means that the slope of this equation is 3.
Answer is:
3 is the slope
The interval for mean sale price is $582
According to statement
The given rates are 560, 468, 685, 534, 658, 593
Now,
Sample mean = X / n
Put the values in it and then
(560+ 468+ 685+ 534+ 658+ 593) / 6 = 582.1667
and use this formula S = sqrt [ X2 - n 2 / (n-1) ]
and put the values in these and
S = sqrt [ X2 - n 2 / (n-1) ] = 95.97179
So, The interval for mean sale price is $582
Learn more about SAMPLE MEAN here
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A given angle measures 90°.. Then, note that the total measurement of the triangle is 180°... Subtract 180° by 90°, and the other angles must add up to 90°!
Good luck!