Assuming you pick 3 students at random, The probability that at least two plan on attending college is 84%.
<h3>Probability</h3>
Using Binomial Distribution
Given:
n = 3
p = 0.75
q = 1-0.95 = 0.25
Hence:
P[≥2] = P[2] + P[3]=(3c2 ×0.75²×0.25) + 0.75³
P[≥2] = P[2] + P[3]=0.421875+0.421875
P[≥2] = P[2] + P[3]=0.84375×100
P[≥2] = P[2] + P[3]=84% (Approximately)
Inconclusion the probability that at least two plan on attending college is 84%.
Learn more about probability here:brainly.com/question/24756209
The answer is 39.
do 2x2x3 (answer is 12) then 27+12.
Answer:
approximately 35.9
Step-by-step explanation:
(5+44+182-20-10)÷(2+5)
(99+182-20-10)÷(7)
(281-20-10)÷(7)
(261-10)÷÷(7)
(251)÷(7)
approximately 35.9
4y= -3x+15
y= (-3/4)x+15/4
y+2= (-3/4)(x-8)
y+2= (-3/4)x+6
y= (-3/4)x+4
Step-by-step explanation:
√3 x² - 2x - √3 = 0
√3 x² - 3x + x - √3 = 0
√3 x(x - √3) + 1(x - √3) = 0
(x - √3 ) (√3 x + 1) = 0
x - √3 = 0 , √3 x +1 = 0
x = √3 , x = -1/√3