Answer:
well um I have to go with 0
Answer:
If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) (0.5)^{t/T} = 400 (0.5)^{t /4}, where T is the half-life period and y(0) is the amount at t = 0 years (initial).
Then at t = 20:
y(20) = 400 (0.5)^{20 /4} = \text{12.5 mg}
Step-by-step explanation:
..............................
85÷(9×5)-(10×4)
85÷(45)-(40)
85/5
17
I think I did this right....
A is not equivalent to 7:3
