Multiply the first equation by -2 to eliminate a variable so it becomes:
-12x+8y=48
4x-8y=-32
Add them together.
-8x=16
x=-2
Plug it in one equation.
6(2)-4y=-24
12-4y=-24
-4y=-12
y=3
Ordered pair is: (-2,3)
Answer:
I) |xz| ≈ 28.6 km
II) |yz| ≈ 34.8 km
Step-by-step explanation:
Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)
|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°
Using Trigonometric ratio - SOHCAHTOA
I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20
|xz| = 20 * Tan 55 = 20 * 1.428
|xz| = 28.56 km
|xz| ≈ <u>28.6 km</u>
<u />
II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|
|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°
|yz| = 20 ÷ 0.574 = 34.84 km
|yz| ≈ <u>34.8 km</u>
<span>If 3x-1=11, then 2x=?
</span><span>
2x + x - 1 = 11
2x = -x +12</span>
It should take about 13.3 hours