Question

10. Write the equation of the line that is parallel tox-3y = 9 and passes through the point (3,-1).​

Answer 1

Answer:

Equation of the line that is parallel tox-3y = 9 and passes through the point  (3,-1) is

$y+1= - \frac{1}{3} (x-2)$

Step-by-step explanation:

Slope of line x-3y = 9 is -1/3

Since Parallel lines have same slope. Therefore slope of line passing through the point (3,-1) is also -1/3.

Equation of line in point slope form is given as

$y-y_1=m(x-x_1)$ ---------- (1)

Here

$m=-\frac{1}{3} \ \ and \ \ (x_1, y_1)= (3, -1)$

substituting values in equation (1)

$y+1= - \frac{1}{3} (x-2)$