1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ira Lisetskai [31]
3 years ago
6

Select three ratios that are equivalent to 5:2. Choose 3 answers:

Mathematics
2 answers:
laila [671]3 years ago
8 0

Answer:

A

C

D

Step-by-step explanation:

if I'm not wrong, I'm sure is that

miv72 [106K]3 years ago
3 0

Answer:

B, E, D

Step-by-step explanation:

You just look for the ones that have the same factors as 5:2

You might be interested in
Solve the equation: 3.2/(z-1/2) = 2.667/(z+1/3)
Luden [163]

Answer:

Z = 2489/533

Step-by-step explanation:

I went on photo math and solved it

7 0
3 years ago
What is the area of a regular nonagon (9 sides) with side length of 15 cm and apothem of 20.6 cm? Round the answer to the neares
Triss [41]
We know that

<span>The nine radii of a regular Nonagon divides into 9 congruent isosceles triangles
</span>therefore
[the area of <span>a regular nonagon]=9*[area of isosceles triangle]

</span>[area of isosceles triangle]=b*h/2------> 15*20.6/2----> 154.5 cm²
so
[the area of a regular nonagon]=9*[154.5]------> 1390.5 cm²

the answer is
1390.5 cm²

5 0
3 years ago
Mr.james runs a petting zoo. he records the number of visitors each week,v, t weeks, after opening the petting zoo. according to
melisa1 [442]

Answer:

\large \boxed{\text{19 visitors/mo}}

Step-by-step explanation:

The average rate of change is the change in the number of visitors divided by the change in the number of months.

1. Change in number of  visitors  

Change in visitors = 182 -125 = 57 visitors

2. Change in number of weeks

Change in time = 5 - 2 = 3 months

3. Average rate of change

\begin{array}{rcl}\text{Average rate of change} &= &\dfrac{\text{change in visitors}}{\text{change in months}}\\\\&= &\dfrac{\text{57 visitors}}{\text{3 mo}}\\\\& = & \textbf{19 visitors/mo}\\\end{array}\\\text{The average rate of change is $\large \boxed{\textbf{19 visitors/mo}}$}

5 0
4 years ago
there are 27 red or blue marbles in the bag the number of red marbles is 5 less than three times the number of blue marbles how
maria [59]
Answer=24 blue marbles and 3 red marbles

r=red marbles
b=blue marbles
b=3(r+5)

27=b+r
substitue b for '3(r+5)'
27=3(r+5)+r
27=3r+15+r
27=4r+15
subtract 15 from both sides
12=4r
divide both sides by 4
3=r

There are 3 red marbles

27=b+r
27=b+3
subtract 3 from both sides
24=b

There are 24 blue marbles
8 0
4 years ago
A2+5a+6=0<br><img src="https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B2%7D%20%20%2B%205a%20%2B%206%20%3D%200" id="TexFormula1" title="
Katarina [22]

we are given

a^2+5a+6=0

we can use factoring formula

a^2-(m+n)a+mn=(a-m)(a-n)

we can compare

and we get

m+n=-5

mn=6

now, we can solve for m and n

and we get

m=-3 , n=-2

now, we can use formula

and we get

a^2+5a+6=(a+3)(a+2)

now, we can set it equal to 0

a^2+5a+6=(a+3)(a+2)=0

(a+3)=0

a=-3

a+2=0

a=-2

so, we will get

a=-2,a=-3.............Answer

3 0
3 years ago
Read 2 more answers
Other questions:
  • What is the area of a trapezoid with bases of 18.8 cm and 21.2 cm and a height of 17.8 cm?
    11·1 answer
  • 7/8=?/48<br> A.42<br> B.13<br> C.1<br> D.6
    13·1 answer
  • PLEASE HELP ITS GEOMETRY :OO
    12·1 answer
  • I just need help on the last question
    13·1 answer
  • What is the value of x in this equation?<br><br> 2x – 12 = -52
    7·2 answers
  • Mr. And Mrs. Doran have a genetic history such that the probability that a child being born to them with a certain trait is 0.14
    10·1 answer
  • Jared measured a house and its lot and made a scale drawing. The scale of the drawing was 5 millimeters : 3 meters. The actual l
    10·1 answer
  • PLEASE HURRY!! ILL GIVE 50 points !!
    14·1 answer
  • Find the area!!!!!!!!!!
    7·1 answer
  • Please answer ASAP<br> Thank you so much!!!!!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!