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Bad White [126]
3 years ago
12

Answer please ?!?!?!

Mathematics
1 answer:
creativ13 [48]3 years ago
7 0

Answer: -9

Step-by-step explanation: -91/6 ≈ -9.167

21/3 ≈ 2.33333

-17/8 ≈ -1.875

-9.167 + 2.3333 + -1.875 = -8.71

Rounded, the answer is -9.

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The lengths of the legs of a right triangle are 7 cm and 24 cm. What is the length of the hypotenuse? 31 cm 25 cm 23 cm 35 cm
melamori03 [73]
Hello there!

You would use the Pythagorean theorem, a^2 + b^2 = c^2, where a and b are legs and c is the hypotenuse.

a^2 + b^2 = c^2
7^2 + 24^2 = c^2
49 + 576 = c^2
625 = c^2

Now square root both sides:

Sq root of 625 = c

25 = c

So, the hypotenuse is 25 cm. Hope this helps!

3 0
4 years ago
Which of the following are the coordinates of vertices of the following square centered at the Origin, with side length b?
adoni [48]

Answer:

Option (3) is correct.

coordinate of given  square centered at the Origin, with side length b is W(\frac{b}{2},\frac{b}{2}), S(\frac{-b}{2},\frac{b}{2}), T(\frac{-b}{2},\frac{-b}{2}) and Z(\frac{b}{2},\frac{b}{2}).

Step-by-step explanation:

Given a square centered at the Origin, with side length b.

We have to find the coordinates of vertices of the square.

Since, the given square is centered at origin (0,0) and length of side is b then x and y axis divide each side in equal part.

Thus, each coordinate of square is \frac{b}{2}.

Since, we know in first quadrant both x and y are positive thus, point W has coordinate (\frac{b}{2},\frac{b}{2})

Also in second quadrant x is negative and y is positive thus, point S has coordinate (\frac{-b}{2},\frac{b}{2})

in third quadrant both x and y is negative thus, point T has coordinate (\frac{-b}{2},\frac{-b}{2})

in fourth  quadrant y is negative and x is positive thus, point Z has coordinate (\frac{b}{2},\frac{b}{2})

Thus, coordinate of given  square centered at the Origin, with side length b is W(\frac{b}{2},\frac{b}{2}), S(\frac{-b}{2},\frac{b}{2}), T(\frac{-b}{2},\frac{-b}{2}) and Z(\frac{b}{2},\frac{b}{2}).

Thus, option (3) is correct.


4 0
3 years ago
Solve the systems of equation by graphing (Picture provided)
padilas [110]

Answer:

The option d

Step-by-step explanation:

find the intersection with x and y

https://tex.z-dn.net/?f=x%3D0%0A

https://tex.z-dn.net/?f=0%2By%3D-9%20%5Clongrightarrow%20y%3D-9%0A

and https://tex.z-dn.net/?f=y%3D0%0A

https://tex.z-dn.net/?f=x%2B0%3D-9

we get the coordinates

https://tex.z-dn.net/?f=(0%2C-9)%2C%20(-9%2C0)

and the same process for another equation

https://tex.z-dn.net/?f=4*(0)%2By%3D-19%20%5Clongrightarrow%20y%3D-19%5C%5C%0A4*x%2B0%3D-19%20%5Clongrightarrow%20x%3D%5Cfrac%7B-19%7D%7B4%7D%20%5C%5C%5C%5C%0A(0%2C-19)%2C%20(%5Cfrac%7B-19%7D%7B4%7D%2C0)%20

and these coordinates are those expressed in the d graph

3 0
3 years ago
What is 5/4 of a right angle?
EastWind [94]
I hope this helps you right angle 90 5/4.90 450/4 112,5
5 0
3 years ago
Are (1,1.5) and (12,4) solutions to the equation y=1/4x+5/4
Amiraneli [1.4K]

Answer:

The first set is a solution, the second is not.

Step-by-step explanation:

Testing by filling in the numbers into the equation:

(1, 1.5): x=1, y=1.5

⇒ 1.5 =? \frac{1}{4} · 1 + \frac{5}{4}

⇒ 1.5 =? \frac{1}{4} + \frac{5}{4}

⇒ 1.5 =? \frac{6}{4}

⇒ 1.5 =? 1.5  ⇒ Correct: is indeed solution to the equation

(12, 4): x=12, y=4

⇒ 4 =? \frac{1}{4} · 12 + \frac{5}{4}

⇒ 4 =? \frac{12}{4}  + \frac{5}{4}

⇒ 4 =? \frac{17}{4} ⇒ Incorrect: this is not a solution for the equation

5 0
2 years ago
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