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nirvana33 [79]
3 years ago
9

Can someone help me with this problem please ​

Mathematics
2 answers:
salantis [7]3 years ago
4 0
Domain: f (x) is the set of all values for which the function is defined
range: the set of all values that f takes
hope this helps
Dafna11 [192]3 years ago
4 0

Answer:

Domain: f(x) = All Real Numbers, Range: f(x) = 2x

Step-by-step explanation:

Seems obvious.

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HELP ASAP FIRST IS BRAINLIEST THANKS!!!!!
White raven [17]

Answer:

B.

Step-by-step explanation:

Since we are talking about horizontal movement, we are manipulating the variable <em>c</em> in f(x) = a|bx + c| + d. We are moving the graph to the right from the parent function, so our answer would have to be B.

6 0
3 years ago
What is the slope of D and E??
Mazyrski [523]

Answer:

-4 and 0

Step-by-step explanation:

Rise over Run would give us the slope.

In the first graph, It goes down 4 while it goes 1 to the right.

This means that -4/1 = -4.

The second graph does not go up or down, meaning 0, while it goes 1 to the right.

This means that 0/1 = 0.

4 0
2 years ago
Which number is the common difference of the sequence -92,-74,-54,-38,-20?
Mkey [24]
The common difference if there is one is the constant difference that occurs between any term and the term before it.... in this case:

There is no common difference, 

dx=18,20,16,18  the difference or velocity is not constant...

d2x=2, -4,2  the acceleration is not constant...

d3x=-6,6  the thrust is not constant  

Now we might be tempted to say that:

d4x=12 and say that that is constant and we COULD make a quartic equation fit all the data points, but without further data points in the sequence there is no mathematical proof that the quartic equation would produce accurate data points outside of the range given...

And solving a system of five equations for five unknowns is tedious for such a problem...a^4+bx^3+cx^2+dx+e=y

8 0
3 years ago
Read 2 more answers
In Littletown, the probability that a baseball team goes to the city playoffs is 0.30. the probability that the team goes to the
salantis [7]

THIS IS THE COMPLETE QUESTION BELOW;

In Littletown, the probability that a baseball team goes to the city playoffs is 0.30. the probability that the team goes to the state playoffs given that the team goes to the city playoffs is 0.20.

What is the probability that a randomly selected team from Littletown goes to the city and state playoffs?

A. 0.10

B.0.50

C. 0.66

D. 0.06

Answer:

OPTION D is correct

d)0.06

the probability that a randomly selected team from Littletown goes to the city and state playoffs is 0.06

Step-by-step explanation:

The probability that a baseball team goes to city playoffs is 0.30.

P(baseball team goes to city playoffs)=0.30

The probability that the team goes to state playoffs given that the team goes to the city playoffs is 0.20.

P(team goes to state playoffs given that the team goes to the city playoffs)=0.20

From our knowledge of set, we know that

P(A | B)= P(A ∩ C)/P(C)

where A= city playoffs

B= state playoffs

P(State play off | city play off)=0.20

P(State play off ∩ city play off)/P(city play off,)=0.20

P(State play off ∩ city play off)/0.30 =0.20

P(State play off ∩ city play off)= 0.30 × 0.20

= 0.06

Hence,the probability that a randomly selected team from Littletown goes to the city and state playoffs is 0.06

7 0
3 years ago
Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
Marat540 [252]

Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}

3 0
3 years ago
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