Question

The function f(t)=t^2+12t-18 represents a parabola.

Answer 1

$y= t^{2} +12t -18 \\ y+18=t^{2} +12t \\ y+18+36=t^{2} +12t+36 \\ y+54=(t+6)^{2} \\ y=(t+6)^{2} -54$
$f(t) = (t+6)^{2} -54$