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Sedaia [141]
3 years ago
5

The tables below show four sets of data:

Mathematics
2 answers:
saul85 [17]3 years ago
8 0

Answer:

set A

Step-by-step explanation:

lana66690 [7]3 years ago
5 0

Answer:

Hence, the set that represent a negative linear association between x and y is:

Set A.

Step-by-step explanation:

We are given 4 sets of data as:

Set A  

x 1 2 3 4 5 6 7 8 9  

y 10 9 8 7 6 5 4 3 2

Set B  

x 1 2 3 4 5 6 7 8 9  

y 3 4 5 6 7 8 9 10 11

Set C  

x 1 2 3 4 5 6 7 8 9  

y 8 6 5 4 3.5 3 2.5 2 2

Set D  

x 1 2 3 4 5 6 7 8 9  

y 1 2.5 2.5 3 4 5 6 8 9

We are asked to determine the set which represent negative linear association between x and y?

Clearly in Set B and Set D the values of y keeps on increasing as the value of x increases; hence they both represent a positive linear association between x and y.

In set C the relationship is non-linear though it is negative.

Clearly in Set A we could see that the the y is related to x as:

        y=11-x or y= -x+11.

Hence, clearly we could see that the relationship is linear and also negative as the value of y keeps on decreasing with increasing x.

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2(11x-6)-18 is equal to 22x-30
rewona [7]

Answer: Yes they are equal

Step-by-step explanation: First you have to solve 2(11x-6)-18:

2(11x-6)-18

22x - 12 - 18

22x - 30

They equal!

7 0
3 years ago
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Solve.
jenyasd209 [6]

Answer:

no solution

Step-by-step explanation:

(you do the exact same you'd do in an equation problem. Get x by itself)

3x+1<2x-2<5x+7

1 < -x-2 < 5x+7

3< -x < 5x+9

3 < -6x < 9

-(1/2) > x > -(3/2)

x can't be bigger than -3 halves and be smaller than -1 half, so the answer is no solution

6 0
4 years ago
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Oduvanchick [21]

Answer:

I just want points hahahaha

7 0
3 years ago
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50 is 1/10 of whatttt I NEED HELP
GREYUIT [131]

Answer:

let \: the \: unknown \:  = x \\ then \:  \frac{x}{10}  = 50 \\ x = 50 \times 10 \\ x = 500 \\ thank \: you

7 0
3 years ago
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Pls say hard very hard​
Simora [160]

(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.

(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?

On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:

50 ≤ score ≤ 60   ==>   50-60

60 < score ≤ 70   ==>   60-70

70 < score ≤ 80   ==>   70-80

80 < score ≤ 90   ==>   80-90

90 < score ≤ 100   ==>   90-100

Then a student who scored a 60 should be added to the 50-60 category.

8 0
3 years ago
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