Graph A since it crosses all 4 regions of the graph
Answer:
Yes, the center of a circle is always and always equidistant from all the points on circumference because that is because what a circle is called. The distance from the center of the circle to the circumference is called the radius and it is constant for any particular circle.
Step-by-step explanation:



= -4c + 14
hence -4c + 14 is the answer ...
hope it helped !!
Answer:

Step-by-step explanation:
We want to find the inverse of
![y = \sqrt[3]{ \frac{x}{3} + 1}](https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7Bx%7D%7B3%7D%20%2B%201%7D%20)
We interchange x and y to get:
![x= \sqrt[3]{ \frac{y}{3} + 1}](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7By%7D%7B3%7D%20%2B%201%7D%20)
We solve for y;

Multiply through by 3

Subtract 1 from both sides:

Therefore the inverse is

The answer is b, as angles ABC is the first half of the angle.