Answer:
h(r) = 6(r+1)+10
Step-by-step explanation:
Just solve for q. Because that's the output. h(r) = q
The area of rhombus is 24 square units.
Step-by-step explanation:
Given,
Length of one diagonal = p = 3+3 = 6 units
Length of other diagonal = q = 4+4 = 8 units
Area of rhombus = 
Area of rhombus = 
Area of rhombus = 
Area of rhombus = 24 square units
The area of rhombus is 24 square units.
Keywords: rhombus, area
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If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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The answer to the first one is A, the second one is 3.58333