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HACTEHA [7]
3 years ago
5

Translate into equations, but do not solve:a The sum of two consecutive odd integers is 52? ​

Mathematics
1 answer:
Rama09 [41]3 years ago
4 0

Answer:

X + (X + 2) = 52

Step-by-step explanation:

Given that the sum of two consecutive odd integers is 52, to determine the equation that solves this problem, the following calculation must be performed:

X + (X + 2) = 52

2X + 2 = 52

X = (52 - 2) / 2

X = 50/2

X = 25

X + 2 =?

25 + 2 = 27

Therefore, the consecutive odd integers are 25 and 27.

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Answer:

Let's solve for x.

4x+2y=345x−6y

Step 1: Add -345x to both sides.

4x+2y+−345x=345x−6y+−345x

−341x+2y=−6y

Step 2: Add -2y to both sides.

−341x+2y+−2y=−6y+−2y

−341x=−8y

Step 3: Divide both sides by -341.

−341x

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Step-by-step explanation:

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the product of two consecutive integers is 420. an equation is written in standard form to solve for the smaller integer by fact
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Start by writing your own expression.

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x(x + 1) = 420

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Step-by-step explanation:

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If a six-sided die(1-6) and a ten-sided die(1-10) are rolled simultaneously, then what is the probability of rolling both with a
AnnyKZ [126]

Answer:

Pr = 0.20

Step-by-step explanation:

Given

n_1 = 10 ---- 10 sided

n_2 = 6 --- 6 sided

Required

P(x_1,x_2 > 4)

First, list out the sample space

S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

(7, 1) (7, 2) (7, 3) (7, 4) (7, 5) (7, 6) (8, 1) (8, 2) (8, 3) (8, 4) (8, 5) (8, 6)

(9, 1) (9, 2) (9, 3) (9, 4) (9, 5) (9, 6) (10, 1) (10, 2) (10, 3) (10, 4) (10, 5) (10, 6)\}

n(S) = 60 --- total outcomes

The event that the outcome of both is greater than 4 is:

x_1,x_2> 4 = \{(5, 5) (5, 6)(6, 5) (6, 6)(7, 5) (7, 6) (8, 5) (8, 6)(9, 5) (9, 6)  (10, 5) (10, 6)\}

n(x_1,x_2>4) = 12

So, the probability is:

Pr = \frac{n(x_1,x_2>4)}{n(S)}

Pr = \frac{12}{60}

Pr = 0.20

6 0
3 years ago
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