Answer:
well if we are going by pattern them possibly 20 or 30 im sorry if its wrong i just need more info on how i should answer it
Step-by-step explanation:
Answer:
A. If 100 pregnant individuals were selected independently from this population, we would expect nothing pregnancies to last less than 184184 days.
Step-by-step explanation:
The mean, standard deviation, and population size can be used for the analysis. In the problem above, the population size is 100 and the estimated number of days for no pregnancy to occur is less than approximately 184 days. This shows that there will not be any pregnancy for any given day that is below the 184th day.
Answer:
idk
Step-by-step explanation:
i 123456788==3-4=2-5=06=20=0-54092=
Dont know 125887q2=5268-2654&+^[email protected]+^25^5#1=^5=2+56=426+
Answer:
False
Step-by-step explanation:
Confidence intervals provide a range for a population parameter at a given significance level. The parameter can be mean, standard deviation etc.
In this example population is the prices of the rents of all the unfurnished one-bedroom apartments in the Boston area
significance level is 95%. Thus, the chance being the true population parameter in the given interval is 95%.
But, "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area." statement is false because the population parameter is missing. Confidence interval may describe population mean for example but it does not describe the <em>whole</em> population.
1/10 = 0.1
2,871,000 ×0.1 = 287,100
Your answer is 287,100
HOPE THIS HELPED :)
