Question

Solve the quadratic equation 8x^2+16x+8=0

Answer 1

Answer:

        x = -1

Step-by-step explanation:

$8x^2+16x+8=0$                  {divide both sides by 8}

$x^2+2x+1=0\\\\a=1\,,\quad b=2\,,\quad c=1\\\\x=\dfrac{-2\pm\sqrt{2^2-4\cdot1\cdot1}}{2\cdot1}=\dfrac{-2\pm\sqrt{4-4}}2=\dfrac{-2\pm0}2=-1$

Answer 2

Answer:

8x²+16x+8=0

x²+2x+1=0

D=4-4=0

x0=-2/2=-1