Answer:
the constant force applied by Kitty is 8 N.
Explanation:
Given;
work done by Kitty, W = 32 J
distance moved by Kitty's trolley, d = 4 m
Let the constant force applied by Kitty = F
The work done by Kitty is calculated as follows;
W = F x d
F = W / d
F = 32 / 4
F = 8 N.
Therefore, the constant force applied by Kitty is 8 N.
Initial angular velocity = 0 (starting from rest)
Final angular velocity = 30 rad/s
Distance traveled = (20 rev)*(2π rad/rev) = 40π rad
Let the angular acceleration be α rad/s².
Then
(30 rad/s)² = (0 rad/s)² + 2*(α rad/s²)*(40π rad)
α = 3.58 rad/s²
Answer: 3.58 rad/s² (nearest hundredth)
Answer:
With a slower speed-perhaps 5 cm/s answer is c