A surface receiving sound is moved from its original position to a position three times farther away from the source of the soun
1 answer:
The intensity of the sound will be B. Nine times lower
Explanation:
The intensity of a sound follows an inverse square law, which means that it is inversely proportional to the square of the distance from the source:
where
I is the intensity
r is the distance from the source
In this problem, the siund has an intensity of I when the receiver is placed at a distance r from the source.
Later, the receiver is placed three times farther away, so the new distance is
r' = 3r
Therefore, the new intensity of the sound will be:
Therefore, the intensity of the sound received will be nine times lower.
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<h2>Answer: Albedo
</h2>
The <u>albedo</u> is an amount that expresses the percentage of radiation a surface reflects with respect to the incident radiation.
In other words:
This amount allows us to know the level of radiation that <u>reflects</u> a surface compared to the total <u>radiation it receives</u>.
According to this, light surfaces such as snow covered ground or white sand will have a higher albedo than dark surfaces such as carbon covered ground. It is also important to note, the albedo will be higher on glossy surfaces than on matte surfaces.
It should be noted that the albedo of the Earth is on average about , which means that part of the radiation received by the Sun is absorbed and another part reflected back to space.