To solve this problem we will apply the concepts related to wave velocity as a function of the tension and linear mass density. This is
![v = \sqrt{\frac{T}{\mu}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7BT%7D%7B%5Cmu%7D%7D)
Here
v = Wave speed
T = Tension
= Linear mass density
From this proportion we can realize that the speed of the wave is directly proportional to the square of the tension
![v \propto \sqrt{T}](https://tex.z-dn.net/?f=v%20%5Cpropto%20%5Csqrt%7BT%7D)
Therefore, if there is an increase in tension of 4, the velocity will increase the square root of that proportion
The factor that the wave speed change is 2.
If you want to tell a friend about a fish you caught or a tree you cut down,
you're going to tell him WHERE you were ... its position in space, 3 numbers,
'x', 'y', and 'z' ... and also WHEN you were ... its position in time, one more
number.
Dimensions are numbers used to describe the location of a point, and the
difference in location between two points. With four numbers, you can exactly
describe the location of anything, and its distance from any other thing, in
space and time.
Answer:
A. F=6.65*10^{-10}N
B. south - north
Explanation:
A) We use the Lorentz force
F = qv X B
|F| = qvB
to calculate the magnitude of the force we need the speed of the of the ball.
![v_{f}^{2}=v_{0}^{2}+2gy\\v_{f}=\sqrt{0+2(9.8\frac{m}{s^{2}})(145m)}=53.31\frac{m}{s}](https://tex.z-dn.net/?f=v_%7Bf%7D%5E%7B2%7D%3Dv_%7B0%7D%5E%7B2%7D%2B2gy%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B0%2B2%289.8%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%29%28145m%29%7D%3D53.31%5Cfrac%7Bm%7D%7Bs%7D)
and by replacing in the formula for the magnitude of the force we have (taking into account the excess of electrons)
![F=(3.8*10^{8})(1.602*10^{-19}C)(53.31\frac{m}{s})(0.205T)=6.65*10^{-10}N](https://tex.z-dn.net/?f=F%3D%283.8%2A10%5E%7B8%7D%29%281.602%2A10%5E%7B-19%7DC%29%2853.31%5Cfrac%7Bm%7D%7Bs%7D%29%280.205T%29%3D6.65%2A10%5E%7B-10%7DN)
B)
b. south - north (by the rigth hand rule)
I hope this is usefull for you
regards
Distance between the two cars is increasing at the rate of 85 mph.
A passenger in Car-1 says that he is at rest in his own frame of reference,
and Car-2 is moving away from him at 85 mph, toward the west.