Two point charges are on the y axis. A 4.50-σC charge (
) is located at y=1.25 cm (
) , and a -2.24-σC charge (
) is located at y=-1.80 cm (
).
The total electric potential at the origin is
.
How to calculate the total electric potential at the origin?
The total electric potential at some point due to several point charges is represented by:

Here,
(Columbic constant)
The total electric potential at point
is the sum of the potentials due to
and
will be:

Substituting the values, we get:

Hence, the total electric potential at the origin is
.4
To learn more about total electric potential, refer to:
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"SEM" or Scanning Electron Microscope is the one among the following choices given in the question that <span>gives the highest amount of magnification. The correct option among all the options that are given in the question is the fourth option or the last option. I hope the answer has come to your help.</span>
Answer:
B. False
Explanation:
An acceleration of 9.8 m/s² means the velocity increases by 9.8 m/s every second.
<u>Metal detectors work by transmitting an electromagnetic field from the search coil into the ground. Any metal objects (targets) within the electromagnetic field will become energised and retransmit an electromagnetic field of their own. The detector’s search coil receives the retransmitted field and alerts the user by producing a target response. metal detectors are capable of discriminating between different target types and can be set to ignore unwanted targets.
</u>
1. Search Coil
The detector’s search coil transmits the electromagnetic field into the ground and receives the return electromagnetic field from a target.
2. Transmit Electromagnetic Field (visual representation only - blue)
The transmit electromagnetic field energises targets to enable them to be detected.
3. Target
A target is any metal object that can be detected by a metal detector. In this example, the detected target is treasure, which is a good (accepted) target.
<em>hope this helps PLEASE MARK AS BRAINLIEST:)</em>
Copper is a better conductor.