I need help please. It’s due tomorrow. I’ve tried three times and gotten the same answer, which my textbook says is wrong

anzhelika [568]

Assuming that there is a typo in the problem and they meant 8 times more than Anne.

5 3/8 * 8 = 40 24/8 = 43 pounds.

8 0

2 years ago

At the first pep rally of the season, the football team and the volleyball team were presented to the student body. During the p

Darina [25.2K]

Answer:

A. f + y ≤ 11

17f + 287 ≤ 242

Step-by-step explanation:

[] Let f be football players and v be volleyball players.

-> The total time must be less than or equal to 242 seconds.

-> If football players talked for 17 seconds, we can write it as 17f.

-> If volleyball players talked for 28 seconds, we can write it as 28v.

[] Coming back to the first point I made, the total time must be less than or equal to 242 seconds.

-> 17f + 28v ≤ 242

[] This is going to be a part of our system of inequalities

-> Because of this, we rule out the following options.

B & D - the football players talk for 17 seconds, not the volleyball players

C - not less than or equal too, only less than

[] This leaves us with the option of A.

-> The first part of it also works. If 11 players can talk to the crowd, then the total of f and v must be equal too or less than 11.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

5 0

2 years ago

Below is the five Number summary for a 136 hikers who recently completed the John muir trail JMT the variable is the amount of t

Helga [31]

Answer:

$IQR = Q_3 -Q_1 = 28-18 = 10$

Now we can find the limits in order to determine outliers like this:

$Left = Q_1 -1.5 IQR = 18 -1.5*10=3$

$Right = Q_1 +1.5 IQR = 18 +1.5*10=33$

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

Step-by-step explanation:

For this case we have the following summary:

$Minimum = 9$ represent the minimum value

$Q_1 = 18$ represent the first quartile

$Median =Q_2= 21$ represent the median

$Q_3 = 28$ represent the third quartil

$Maximum=56$ represent the maximum

If we use the 1.5 IQR we need to find first the interquartile range defined as:

$IQR = Q_3 -Q_1 = 28-18 = 10$

Now we can find the limits in order to determine outliers like this:

$Left = Q_1 -1.5 IQR = 18 -1.5*10=3$

$Right = Q_1 +1.5 IQR = 18 +1.5*10=33$

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

7 0

3 years ago

PLS AWNSER NOW

sattari [20]

Answer:

600

Step-by-step explanation:

2000/10=200. 200x3=600

4 0

2 years ago

Find the perimeter of the given figure, round to the nearest tenth

labwork [276]

Answer:

2√424 + 62 ≈ 103.1825205639 ≈ 103.2 units

Explanation:

Given the two baselengths, and the perpendicular height of the trapezoid, you can actually find the perimeter through the pythangorean theorem because the perpendicular height or height that forms a right or 90 degree angle makes a right triangle(2 be exact because this is an isoceles trapezoid which has two adjacent right triangles).

This is true of the trapezoid is icosceles.

6 0

2 years ago

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