of the candy is not m&m's.
Step-by-step explanation:
Given,
Total pieces of candy = 140
Number of m&m's = 35
Fraction = 
Fraction = 
Both 35 and 140 are multiples of 7, therefore,
Fraction of m&m's = 
As the number of m&m's fraction and not m&m's fraction will make a total of 1, therefore
fraction of m&m's + fraction of not m&m's = 1
fraction of not m&m's = 1 - fraction of m&m's
fraction of not m&m's = 
fraction of not m&m's =
of the candy is not m&m's.
Keywords: fraction, subtraction
Learn more about fractions at:
#LearnwithBrainly
(x - 4)²
(x - 4)(x - 4)
x² - 4x - 4x + 16
x² - 8x +16
Answer:
The system of inequalities that represents this situation is:
x+y≥10
6x+4y≤50
Step-by-step explanation:
As the statement says that Laura wants to provide one party favor per person to at least 10 guests, the first inequality would indicate that the number of stuffed animals plus the number of toy trucks should be equal or greater than 10:
x+y≥10
Also, the statement indicates that miniature stuffed animals cost $6.00 each and the toy trucks cost $4.00 each and that Laura has $50. From this, you would have an inequality that indicates that 6 for the number of miniature stuffed animals and 4 for the number of toy trucks would be equal or less than 50:
6x+4y≤50
The answer is that the system of inequalities that represents this situation is:
x+y≥10
6x+4y≤50
Answer:
x = 0.5
y = -1/4 or -0.25
Step-by-step explanation:
x + 6y = 2
3x + 2y = 10
Multiply a number by any of the equations to get numbers of the same variable
3x + 18y = 6
3x + 2y = 10
3x - 3x = 0
NB: subtract evenly if u subtract down from top make sure u subtract down from top throughout
16y = -4
16y/16 = -4/16
y = -1/4 or -0.25
to find the x value, any where you see y u put in the y value(-0.25)
So u'll pick just one of the equations above
x + 6(0.25) = 2
x + 1.5 = 2
x = 1.5 + 2
x = 0.5
Answer:
p^3 / q^12
Step-by-step explanation:
p^6 q^4
------------------
p^3 q^16
We know a^b / a^c = a^(b-c)
First with variable p
p^6 / p ^3 = p^(6-3) = p^3
Then with variable q
q^4 / q^16 = q^(4-16) = q^-12 and a^-b = 1/ a^b = 1 /q^12
p^3 * 1/ q^12
p^3 / q^12
