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Ratling [72]
2 years ago
7

Determine the number positive real zeros of the polynomial below. (Type answer in as a whole number)f(x)=x^5+3x^2-4x+2

Mathematics
1 answer:
alexandr402 [8]2 years ago
6 0

Answer:

The number of positive real zeros is 2 or 0

Step-by-step explanation:

Given

f(x)=x^5+3x^2-4x+2

Required

Number of positive real zeros

Using Descartes rule of signs;

We write out the signs in front of each term;

Sign = + + - +

Count the number of times the sign alternate; i.e. from positive to negative and from negative to positive

From positive to negative, we have: 1 (i.e. + - )

From negative to positive, we have: 1 (i.e. - +)

Add up the count

count = 1+1

count = 2

<em>Hence, the number of positive real zeros is 2 or 0</em>

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