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Ksju [112]
3 years ago
9

Questions number 1

Mathematics
1 answer:
Brut [27]3 years ago
8 0

9514 1404 393

Answer:

  145.3 square inches

Step-by-step explanation:

The lateral area of the cylinder is given by ...

  LA = 2πrh

  LA = 2π(2.5 in)(9.25 in) = 46.25π in²

  LA ≈ 145.3 in²

About 145.3 square inches of paper is used for the label.

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Four baskets contain scented soaps. The baskets contain 9, 9, 11, and 15 soaps. If the soaps are divided evenly among the basket
jeka94

Answer:

11

Step-by-step explanation:

9+9+11+15 is 44 44/4 is 11

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Find the value of x. Express your answer in simplest radical form
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Since x=x, this is an isosceles right triangle.  By the Pythagorean Theorem:

h^2=a^2+b^2  (the hypotenuse squared is equal to the sum of the squared sides)

5^2=x^2+x^2

25=2x^2

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x^2=25/2

x=√(25/2)

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7 0
3 years ago
A container contains 10 diesel engines. the company chooses 8 engines at​ random, and will not ship the container if any of the
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Answer:

16/25

Step-by-step explanation:

We just have to find the probability that the 8 non-defects are chosen.

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2. Chance second defect is undetected: <em>4/5</em>

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3 years ago
-8 + (-2)<br> Plz answer
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5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

6 0
3 years ago
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