3 years ago

What is the product? (6r − 1)(−8r − 3)

Mathematics

2 answers:

xxMikexx [17]3 years ago

7 0

-2r - x - 3 ............

trasher [3.6K]3 years ago

4 0

-58r+3 is the answer just use a two way table to figure it out

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denis-greek [22]

Answer:

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3 years ago

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3 years ago

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On a piece of paper, graph y= -2x-3. Then determine which answer<br> matches the graph you drew.

DerKrebs [107]

The correct answer is C !!

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3 years ago

Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh

fredd [130]

With

$\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k$

we have

$\mathrm d\vec r=(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt$

The vector field evaluated over this parameterization is

$\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k$

so the line integral is

$\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt$

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6 0

3 years ago

Plz help me find answer. what are the coordinates of slope when y= x/1–x² when dy/dx=1

vova2212 [387]

Step-by-step explanation:

dy/dx

= d/dx [x / (1 - x²)]

= [(1 - x²)(1) - (x)(-2x)] / (1 - x²)²

= (1 + x²) / (1 - x²)².

When dy/dx = 1, (1 + x²) / (1 - x²)² = 1.

=> 1 + x² = 1 - x²

=> 2x² = 0, x = 0.

Also when x = 0, y = (0) / [1 - (0)²] = 0.

Hence the coodinates is (0, 0).

8 0

2 years ago