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Nimfa-mama [501]
3 years ago
9

if about 32,834.5 kilobytes of memory is still available how many more pictures can they take if you have only taken 43 pictures

?
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
5 0
That will depend, you have to ask yourself first how many kilobytes one picture is. Let's just say that the size of one picture is 100 kb (which is the average size of a picture) Then first you multiply 100 kb with the number of pictures which is 43. Now you have a total used up memory of 4300 kb. After that, you minus the used up memory which is 4300 kb, to the total available space which is 32,834.5 and you will get an available space of 28534.5 kb. After that, you divide the remaining available space with the size of each picture. So this will be 28534.5 divided by 100. You will get 285. You can still take 285 pictures. 
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Which of the following notations correctly describe the end behavior of the polynomial graph below?
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The end behaviour of the polynomial graph is (b) x ⇒ +∝, f(x) ⇒ -∝ and x ⇒ -∝, f(x) ⇒ -∝

<h3>How to determine the end behaviour of the polynomial graph?</h3>

The polynomial graph represents the given parameter

This polynomial graph is a quadratic function opened downwards

Polynomial function of this form have the following end behaviour:

  • As x increases, f(x) decreases
  • As x decreases, f(x) decreases

This is represented as

x ⇒ +∝, f(x) ⇒ -∝ and x ⇒ -∝, f(x) ⇒ -∝

Hence, the end behaviour is (b)

Read more about end behaviour at

brainly.com/question/1365136

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1 year ago
The parallelogram shown represents a map of the boundaries of a natural preserve. Walking trails run from points A to C and from
Citrus2011 [14]

y+2 = 3y-4 =

y+6 = 3y

6 =2y

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answer is C

4 0
3 years ago
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What is the answer to this question?
Anuta_ua [19.1K]
I hope this helps you

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This question wants you to find a common denominator for the fractions.
This means finding the LCM, least common multiple, for 21 and 9.
This can be done by listing the multiples for each number until they meet at a common one.

9:
9
18
27
36
45
54
63

21:
21
42
63

This means the LCM of 21 and 9 is 63.
So the lowest possible common denominator is 63.

21 • 3 = 63
So you have to multiply the numerator of 2/21 by 3 as well.
2 • 3 = 6
2/21 = 6/63

Now do the same for 1/9.
9 • 7 = 63
Multiply the numerator, 1, by 7.
1 • 7 = 7
1/9 = 7/63

So in the first blanks, you would put 6/63 for what 2/21 is equal to and 7/63 for what 1/9 is equal to.

7/63 is greater than 6/63.
7/63 > 6/63
That means 1/9 > 2/21
So 2/21 < 1/9 is the answer to the last blank.

Hope this helps!
6 0
3 years ago
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