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astraxan [27]
3 years ago
14

I’ll give thanks, 5 stars and brainliest

Mathematics
2 answers:
NISA [10]3 years ago
8 0

Answer:

25,36,49,64,81,100

................................

Savatey [412]3 years ago
8 0

Answer:

Your answer is 1, 4, 9, 16, 25, 36, 49, 64, 81, 100.

Step-by-step explanation:

1 - 4  

+ 3

4 - 9

+ 5

9 - 16

+ 7

+9, +11, +13, +15, +17, +19...

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In usatestprep</span>
7 0
3 years ago
Read 2 more answers
You are purchasing soft drinks for the company annual party. You expect about 32 people to be there. You want to allow at least
qaws [65]
 
<span>32*18=576 oz. </span>



<span>Store A offers 24-12 oz cans for $5.89. That means $5.89 gets you 288 oz. Store B offers 12-12oz cans for $3.79, so that means $3.79 gets you 144oz. </span>

<span>Store A is $5.89 per every 288 oz. You need 576 oz, which is double that. That means it will cost you twice as much as it would buying 24-12 oz cans: </span>
<span>$5.89*2=$11.78 </span>

<span>Store B is $3.79 for 144 oz. As previously stated, you need 576 oz, so you'll need to buy 4 12-packs of 12 oz cans: </span>
<span>$3.79*4=15.16 </span>

<span>So not only is Store A a better deal, but they'll save you $15.16-$11.78=$3.38 dollars. </span>
5 0
4 years ago
Seraphina is driving two hours to visit her family. For the first hour, she traveled at a speed of 62 miles per hour. Then, in t
Murljashka [212]

Answer:

11.3%

Step-by-step explanation:

\%\ increase=\frac{final-initial}{initial} \times 100\%\\\%\ increase=\frac{69-62}{62} \times 100\%\\\%\ increase=\frac{7}{62} \times 100\%\\\%\ increase=11.3\%

6 0
3 years ago
Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
4 years ago
Please help this quiz is worth a lot of point
sergiy2304 [10]

Answer:

YZ = 1

XY = 1.5

XYZ 1.33

Step-by-step explanation:

5 0
2 years ago
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