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Naddik [55]
2 years ago
15

Consider the equation 2y - 4x = 12

Mathematics
2 answers:
Vlad [161]2 years ago
8 0

Answer:

The Answer Is A.–y – 2x = 6

Step-by-step explanation:

The first person is wrong, but Edge says that it's that answer for me.

Aleks [24]2 years ago
4 0

Answer:

y = 2x + 6 and 2y-4x=12 are the same line, so have infinitely many solutions.

Step-by-step explanation:

2y - 4x = 12

This is the same as y = 2x + 6

You might be interested in
You have two squares. The larger square has a side of 3 more than the smaller square. If the combined area of the two squares is
joja [24]
The length of the SMALLER square is:
B. 5

Basically I tested each answer choice and see if all the information matches it.
Lets check how my answer is correct:
We know that:
The length of the bigger square is 3 more than the smaller square’s length.
The areas of both squares add up to 89 cm^2
length of the SMALLER square is: 5 cm
length of the LARGER square:
5 + 3 = 8 cm

Area of smaller square:
5^2 = 25 cm^2

Area of bigger square:
8^2 = 64 cm^2

ADD UP BOTH AREAS OF SQUARES:
25 + 64 = 89 cm^2

Hope this helps!
3 0
3 years ago
Read 2 more answers
Write the equation of the line with the given slope and y intercept.<br> m = 0.25 b = 6
Sloan [31]

Answer:

y=−2x+6

Step-by-step explanation:

the equation of a line in slope-intercept form is. y=−2x+6 is the equation.

6 0
3 years ago
Read 2 more answers
I want to know the answer to this question <br><br> through: (-4, 0), parallel to y =1/2x +3
netineya [11]

parallel lines have negative reciprocal slopes

so 1/2 becomes -2

point slope form

y-y1 =m(x-x1)

y-0 = -2(x--4)

y =-2(x+4)

y=-2x-8

5 0
2 years ago
If f(z) = z2 + c is iterated with an initial value of 2 + 3i and z1 = -1 + 15i, find c. a. 7 - 4i c. 4 - 3i b. 7 + 4i d. 4 + 3i
Ugo [173]

Answer: choice D) 4 + 3i

=======================================

Plug in the initial value z = 2 + 3i. Simplify.

f(z) = z^2 + c

f(2+3i) = (2+3i)^2 + c

f(2+3i) = (2+3i)*(2+3i) + c

f(2+3i) = 2(2+3i) + 3i(2+3i) + c

f(2+3i) = 4 + 6i + 6i + 9i^2 + c

f(2+3i) = 4 + 12i + 9i^2 + c

f(2+3i) = 4 + 12i + 9(-1) + c

f(2+3i) = 4 + 12i - 9 + c

f(2+3i) = -5 + 12i + c

The initial z value is z = 2+3i, which when plugged into f(z) leads to the term z1 = -1+15i. The input is 2+3i and the output is -1+15i

Set f(2+3i) equal to the output z1 = -1+15i and solve for c

f(2+3i) = z1

-5 + 12i + c = -1 + 15i

c = -1 + 15i + 5 - 12i

c = 4 + 3i

So if c = 4 + 3i, then f(z) = z^2 + c will have f(2+3i) = -1 + 15i

3 0
3 years ago
The expression of 20-31 gives us the distance between the numbers 20 and 31 write a similar expression for the distance between
horrorfan [7]

Answer:

After simplifying, our answer is 10

Step-by-step explanation:

20-31 gives the distance between 20 and 30

Now, for -5 and -15

The similar expression to write will be -5-(-15)

Simplifying this, we have;

That would be -5+15 = 10

6 0
3 years ago
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