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jekas [21]
3 years ago
11

Write the equation of the line with the given slope and y intercept. m = 0.25 b = 6

Mathematics
2 answers:
Sloan [31]3 years ago
6 0

Answer:

y=−2x+6

Step-by-step explanation:

the equation of a line in slope-intercept form is. y=−2x+6 is the equation.

SCORPION-xisa [38]3 years ago
5 0
=2x =6 hope I helped :)
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The correct answer is D.12
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The price of an item has been reduced by <br> 45% <br> . The original price was <br> $17
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Price is reduced by 45%. Which means that the new price is 55% of the original.
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There are 24 girls on the track team. First race2/3 girl ran.only1/4 girl ran in second race. 1/6 on third race. Hiw many more g
alukav5142 [94]

Answer:

10 more girls

Step-by-step explanation:

So here 2/3 of 24 ran for first race

Then it gives us that 16 girls ran for first race.

Next, 1/4 of 24 ran for second race

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3 years ago
Which chart belong with the graph at the right?
agasfer [191]

Answer:

Chart nº 2

Step-by-step explanation:

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6 0
3 years ago
A recent broadcast of a television show had a 10 ​share, meaning that among 6000 monitored households with TV sets in​ use, 10​%
Kisachek [45]

Answer:

Null and alternative hypothesis

H_0: \pi \geq0.25\\\\H_1: \pi

Test statistic z=-26.82

P-value P=0

The null hypothesis is rejected.

It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

Step-by-step explanation:

We have to perform a hypothesis test of a proportion.

The claim is that less than 25% were tuned into the program, so we will state this null and alternative hypothesis:

H_0: \pi \geq0.25\\\\H_1: \pi

The signifiance level is 0.01.

The sample has a proportion p=0.1 and sample size of n=6000.

The standard deviation of the proportion, needed to calculate the test statistic, is:

\sigma_p=\sqrt{\frac{\pi(1-\pi)}{N} } =\sqrt{\frac{0.25(1-25)}{6000} } =0.0056

The test statistic is calculated as:

z=\frac{p-\pi+0.5/N}{\sigma_p} =\frac{0.1-0.25+0.5/6000}{0.0056}=\frac{-0.1499}{0.0056}  =-26.82

As this is a one-tailed test, the P-value is P(z<-26.82)=0. The P-value is smaller than the significance level (0.01), so the effect is significant.

Since the effect is significant, the null hypothesis is rejected. It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

3 0
3 years ago
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