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mezya [45]
3 years ago
12

Pls help I’ll brainlest ASAP

Mathematics
1 answer:
tatyana61 [14]3 years ago
6 0
Ok so 36-12=24 and 24 divided by 3 (the triplets) is 8 would mean they are all 8. :) I’m not sure about all of the blanks though :/ sorry
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PLZ SOMEONE ANSWER ASAP
Tomtit [17]
Y>3 only rules out B.  B,D,E,F all satisfy 2x<y.  So

ANSWER: D E F




4 0
3 years ago
Evaluate the expression when p= -24 and q = 4.
Talja [164]

(2 \times  - 24) \div  - 4
which comes out as 12
3 0
3 years ago
Solve the following inequality.<br><br> 9x−2&gt;43
kirill [66]

Answer:

x > 5

Step-by-step explanation:

Given

9x - 2 > 43 ( add 2 to both sides )

9x > 45 ( divide both sides by 9 )

x > 5

8 0
3 years ago
You want to buy an item that costs $100. Which of these is the most cost-effective choice for buying the item?. a. using a paid
Paraphin [41]

<u>Answer</u>

c. buying it at a 10 percent discount without sales tax.


<u>Explanation</u>

We are going to compare the 3 choices and then determine the most cost effective.

<em>a. using a paid membership card to buy it at a 10 percent discount.</em>

10% of $100 = 10/100×100 = $10

cost = $100 - $10 = $90

On top of this $90 there is the charges of the membership card.

<em> b. buying it online at a 10 percent discount with a $5 shipping charge.</em>

100%-10% = 90%

90% of 100 = $90

Cost: $90 + $5 = $95

<em>c. buying it at a 10 percent discount without sales tax.</em>

100% - 10% = 90%

90/100 × 100 = $90. This is the must cost effective method since there is no other cost involved.


7 0
3 years ago
Read 2 more answers
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
3 years ago
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