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Mandarinka [93]
3 years ago
13

What is the length of VS?

Mathematics
1 answer:
hram777 [196]3 years ago
4 0

Answer:

use pythag

half 5 = 2.5

half 12 = 6

6^2 + 2.5^2=42.25

42.25 sprout =13/2= 6.5

answer = 6.5

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Rachel has 30 pounds of a mixture of candy that sells for $1.00/lb. If lollipops sell for $0.95/lb and caramel candies sell for
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L = pounds of lollipop
c = pounds of caramel candies

0.95l + 1.10c = 30 ($0.95/lb & $1.10/lb)
l + c = 30 (mixture sells for $1/lb)
c = 30 - l

0.95l + 1.10(30 - l) = 30 (Substitution)
0.95l + 33 - 1.10l = 30
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l = 20lbs

Hope this helps.
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4 years ago
in which category is the cost of living in Atlanta almost three times the cost of living in Philadelphia
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Because atlanta is a bigger city

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The local utility company averages rates to determine a standard monthly charge for area businesses. If you are charged $150 for
lisabon 2012 [21]
The average of 3 numbers is their total divided by 3.
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Rounded to the nearest dollar, the average charge for the period is $178 per month.
6 0
4 years ago
If the length width and height of a cube all quadruple what happened to the volume of the cube
lorasvet [3.4K]

Answer:

if the length, width and height of a cube quadruple, then the volume of the cube will be multiplied by 64.

Step-by-step explanation:

Given a cube of width W, height H and length L, the volume of the cube will be: Volume = W*H*L

If all the three parameters quadruple, then:

New Width = 4W

New Height = 4H

New Length = 4L

New Volume = 4W*4H*4L = 64WHL

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3 years ago
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If f(x) = 3x2 − 8x, 0 ≤ x ≤ 3, evaluate the Riemann sum with n = 6, taking the sample points to be right endpoints.
denis23 [38]

Split up the interval [0, 3] into 6 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]

The right endpoints are given by the arithmetic sequence,

r_i=0+\dfrac i2=\dfrac i2

with 1\le i\le6.

We approximate the integral of f(x) on the interval [0, 3] by the Riemann sum,

\displaystyle\int_0^3f(x)\,\mathrm dx=\sum_{i=1}^6f(r_i)\Delta x_i

\displaystyle=\frac{3-0}6\sum_{i=1}^6\left(3{r_i}^2-8r_i\right)

\displaystyle=\frac12\sum_{i=1}^6\left(\frac{3i^2}4-4i\right)

\displaystyle=\frac38\sum_{i=1}^6i^2-2\sum_{i=1}^6i

Recall the formulas,

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6

Then the value of the integral is approximately

\displaystyle=\frac38\cdot\frac{6\cdot7\cdot13}6-2\cdot\frac{6\cdot7}2=\boxed{-\frac{63}8}=-7.875

Compare to the exact value of the integral, -9.

7 0
3 years ago
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