Answer:
y=2/3x
Step-by-step explanation:
Hi there!
We want to find the equation of the line that passes through the point (3,2) and has a slope of 2/3
We can write the equation of the line in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
Since we are already given the slope, we can substitute it into the equation as m
y=2/3x+b
Now we need to find b
Since the equation passes through the point (3,2), we can plug its values into the equation to solve for b
Substitute 3 as x and 2 as y into the equation:
2=2/3(3)+b
Multiply
2=2+b
Subtract 2 from both sides
0=b
Substitute 0 as b into the equation
y=2/3x+0
Simplify:
y=2/3x
Hope this helps!
Answer:
the number of circles is 3
the number of square is 9
the number of triangle is 10
Step-by-step explanation:
Let the number of square = s
let the number of circle = c
let the number of triangle = t
let the total number of the shapes = y
15 < y < 25
y = s + c + t ---- (i)
s = c + 6 ------ (ii)
c + 7 = t ------ (iii)
y = (s) + (c) + (t)
y = (c + 6) + (c) + (c + 7)
y = 3c + 13
15 < y < 25
15 < 3c + 13 < 25
15 - 13 < 3c < 25 -13
2 < 3c < 12
2/3 < c < 12/3
0.67 < c < 4
Thus, number of circle is greater 1 but less than 4
c = 3
s = 3 + 6 = 9
t = 3 + 7 = 10
Answer:
p^2 + q^2 = 22/9.
Step-by-step explanation:
For a quadratic function ax^2 + bx + c if the zeroes are A and B then
A + B = -b/a and AB = c/a.
2x^2 - 7x + 3
Now p and q are the zeroes of the above function so
p + q = 7/3 and pq = 3/2.
Now p^2 + q^2 = (p + q)^2 - 2pq
= (7/3)^2 - 2* 3/2
= 49/9 - 3
= 49/4 - 27/9
= 22/9.
Answer:
there are 100 children in the class
Answer:
Step-by-step explanation:
Domain: I don't see any restrictions on the domain, although at some point y will become exceedingly large.
Range: -9 to infinity
Increasing Interval: x>2
Decreasing Interval: x <2
End behavior:
- as x ⇒∞, y⇒∞
