Question

Suppose that on the average, 7 students enrolled in a small liberal arts college have their automobiles stolen during the semester. What is the probability that more than 1 student will have his automobile stolen during the current semester? Round your answer to four decimal places.

Answer 1

Answer:0.9991

Step-by-step explanation:

The Poisson distribution probability formula is given by :-

$P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}$, where \lambda is the mean of the distribution and x is the number of success

Given : $\lambda=7$

The probability that more than 1 student will have his automobile stolen during the current semester is given by :-

$P(x\geq1)=1-P(x=0)=1-(\dfrac{e^{-7}7^0}{0!})\\\\=1-e^{-7}=0.99908811\approx0.9991$

Hence, the  probability that more than 1 student will have his automobile stolen during the current semester =0.9991