All categories

2 years ago

80% of x is 48. Write an equation that represents this statement.

Mathematics

1 answer:

jekas [21]2 years ago

3 0

48/x = 80/100
(To solve this you cross multiply and divide)

You might be interested in

Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

2 years ago

A car travles 75 miles on 3 gallons of gasoline how much gasoline will it need to go 342 miles

PolarNik [594]

If u find how many miles for 1 gallon, there are 25 miles so then divide 342 by 25 and u get 13.68 gallons

8 0

3 years ago

Please help solve ty

kobusy [5.1K]

The answers are blurry and hard to read. If you repost this question with a clearer picture, I would be happy to try and answer as best I can! :)

4 0

2 years ago

P(x) = 2x4 − x3 − 4x2 + 10x − 4

avanturin [10]

Answer: 2x ^4 +7x−4x ^2 −4

Step-by-step explanation:

2x ^4 −x*3−4x ^2 +10x−4

2x ^4 −3x−4x ^2 +10x−4

2x ^4 +(−3x+10x)−4x ^2 −4

2x ^4 +7x−4x ^2 −4

7 0

3 years ago

Dani takes her two friends out for lunch. Dani's meal costs $5.72 and her friends' meals are $4.89 and $7.30. Dani pays for the

Solnce55 [7]

The answer is A. 2.09

7 0

3 years ago

Read 2 more answers