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3 years ago

14

An architect is creating a scale model of a building. The building will stand at 1,000 yards, and the scale shows that 2 inches

= 10 feet. How tall will the scale model be

1 answer:

andrew-mc [135]3 years ago

6 0

Well 3 feet equal a yard, and you do 1000 multiplied by 3 is 3000. And then you do 3000 divided by 10, and you get 300.

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16. Which is greater, 4^-2 or<br> 2^-4? How do you know?<br> Those are exponents.

gladu [14]

Answer:

Both are equal to $\frac{1}{16}$

Step-by-step explanation:

If the exponent is negative we can turn it into a fraction and make it positive.

This means the number goes to the denominator and the numerator becomes one. Therefore the following.

$4^{-2} = \frac{1}{4^{2} } =\frac{1}{16}$

$2^{-4} =\frac{1}{2^{4} } = \frac{1}{16}$

4 0

3 years ago

Solve for r<br><br>v = 4/3 r^3<br>

sergejj [24]

Answer:

$r=\sqrt[3]{\frac{3v}{4} }$

Step-by-step explanation:

To solve for $r$ :

$v=\frac{4}{3}r^{3}$ (given)

$\frac{3v}{4}=r^{3}$ (times $\frac{3}{4}$ on both sides)

$r=\sqrt[3]{\frac{3v}{4} }$

I hope this helps :)

8 0

3 years ago

What does x equal? Plz hurry. First to answer correctly will be marked brainliest ASAP.

svet-max [94.6K]

Answer:

6.0

Step-by-step explanation:

This involves using SOH CAH TOA.

we use Sin as we want to find x (which is side O, and we are given H).

So we get sin37 = O/H

= x/10

so x = 10 sin 37 = 6.018... = 6.0 to the nearest tenth.

3 0

3 years ago

Help please? It involves functions

Ilia_Sergeevich [38]

Answer:NO, NO, YES

Step-by-step explanation:

7 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago