Answer:
ooh bruh it pink
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).
Consider option A.
1st transformation 
will map vertices of the square into points
2nd transformation = reflection over y = 1 has the rule (x,2-y). So,
These points are exactly the vertices of the initial square.
Consider option B.
1st transformation 
will map vertices of the square into points
2nd transformation = reflection over x = 3 has the rule (6-x,y). So,
These points are exactly the vertices of the initial square.
Consider option C.
1st transformation 
will map vertices of the square into points
2nd transformation = reflection over y = -x + 7 will map vertices into points
These points are exactly the vertices of the initial square.
Consider option D.
1st transformation 
will map vertices of the square into points
2nd transformation = reflection over y = -x + 2 will map vertices into points
These points are not the vertices of the initial square.
Sin = opposite/hypothenuse
Given opposite = 16
Hypothenuse = ?
Use Pythagorean theorem to find hypothenuse
12^2 + 16^2 = h^2
144 + 256 = h^2
h^2 = 400, h = 20
You know hypothenuse is 20
Opposite/hypothenuse
Solution: 16/20
Simplify if you need to (4/5)
Answer:
.25 in per hour
Step-by-step explanation:
you just divide 28/7 and you get the per hour and you can double check your work by doing .25 * any hour until you get 28
Answer: option <span>D) y=x, x-axis, y=x, y-axis</span>.
I first thought it was the option C) and I tried with it but it was wrong. This is how I dit it.
Option C step by step:
<span>1) Reflection over the x - axis => point with coordinates (a,b) is transformed into point with coordinates (a, -b)
2) Reflection over the line y = x => point with coordinates (a, -b) is transformed into point with coordinates (-b,a)
3) New feflection over the x - axis => (-b,a) transforms into (-b, -a)
4) New reflection over the line y = x => (-b,-a) transforms into (-a,-b)
Which shows it is not the option C).
Then I probed with option D. Step by step:
1) Reflection over the line y = x => (a,b) → (b,a)
2) Reflection over the x-axis => (b,a) → (b,-a)
3) Reflection over the line y = x => (b,-a) → (-a,b)
4) Reflection over the y-axis => (-a,b) → (a,b).
So, this set of reflections, given by the option D) transforms any point into itself, which proofs that the option D) is the right answer.
</span>
