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k0ka [10]
3 years ago
9

a jeweler makes a necklace using red and blue beads. The jeweler has 24 red beads and 36 blue beads. What is the greatest number

of identical bracelets the jeweler if all beads are used?
Mathematics
1 answer:
aleksley [76]3 years ago
5 0

Answer:

60

Step-by-step explanation:

24+36

20+30=50

4+6=10

50+10=60

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WILL mark answer right if gotten right
marin [14]

Answer:

ooh bruh it pink

Step-by-step explanation:

7 0
3 years ago
Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
Pls help, question on picture, will do brainliest if right<br> no links!!!!!
Flura [38]
Sin = opposite/hypothenuse
Given opposite = 16
Hypothenuse = ?
Use Pythagorean theorem to find hypothenuse

12^2 + 16^2 = h^2
144 + 256 = h^2
h^2 = 400, h = 20

You know hypothenuse is 20
Opposite/hypothenuse

Solution: 16/20
Simplify if you need to (4/5)
5 0
3 years ago
Read 2 more answers
A snow storm hit Sanford with 7 inches of snow in 28
Nutka1998 [239]

Answer:

.25 in per hour

Step-by-step explanation:

you just divide 28/7 and you get the per hour and you can double check your work by doing .25 * any hour until you get 28

7 0
3 years ago
Read 2 more answers
What set of reflections would carry rectangle ABCD onto itself?
Furkat [3]
Answer: option <span>D) y=x, x-axis, y=x, y-axis</span>.

I first thought it was the option C) and I tried with it but it was wrong. This is how I dit it.

Option C step by step:

<span>1) Reflection over the x - axis => point with coordinates (a,b) is transformed into point with coordinates (a, -b)

2) Reflection over the line y = x  => point with coordinates (a, -b) is transformed into point with coordinates (-b,a)

3) New feflection over the x - axis => (-b,a) transforms into (-b, -a)

4) New reflection over the line y = x => (-b,-a) transforms into (-a,-b)

Which shows it is not the option C).

Then I probed with option D. Step by step:

1) Reflection over the line y = x => (a,b) → (b,a)

2) Reflection over the x-axis => (b,a) → (b,-a)

3) Reflection over the line y = x => (b,-a) → (-a,b)

4) Reflection over the y-axis => (-a,b) → (a,b).

So, this set of reflections, given by the option D) transforms any point into itself, which proofs that the option D) is the right answer.
</span>
7 0
4 years ago
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