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dimulka [17.4K]
3 years ago
8

I'm struggling with this one ​

Mathematics
2 answers:
mezya [45]3 years ago
8 0

Answer:

it's the third one cause its square root so x can never be less then 0 but it can go in infinitely

Ede4ka [16]3 years ago
4 0
The third 1111111111111111111111111111111111
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What is the product? (2y + 3) (3y^2 +4y + 5)
Furkat [3]

Answer:

6y³ + 17y² + 22y + 15

Step-by-step explanation:

(2y + 3)(3y² + 4y + 5)

6y³ + 8y² + 10y + 9y² + 12y + 15

6y³ + 8y² + 9y² + 10y + 12y + 15

6y³ + 17y² + 22y + 15

8 0
2 years ago
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What is the 32nd term of 311, 305, 299
nata0808 [166]

Answer:

503

Step-by-step explanation:

For an arithmetic sequence, the n-th term is found by

a_n = a_1 + (n - 1)d

To find d (the common difference) we can simply subtract one of the terms by the last, for example:

d = 299 - 305 \\d = -6 \\

The common difference must be the same throughout the entire sequence, so we can do it once more just to be sure:

d = 305 - 311\\d = -6

We also have to know that a_1 stands for the first term of the sequence, which in this case is 311.

Now that we know this, let's find the 32nd term

a_{32} = 311 + (32 - 1)-6\\a_{32} = 311 + 192\\a_{32} = 503

Good luck!

4 0
2 years ago
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The function​ s(t) represents the position of an object at time t moving along a line. Suppose s (3 )equals 156 and s (6 )equa
bixtya [17]

Answer: The average velocity of the object over the time interval [3,6] is 20.

Step-by-step explanation:

Since we have given that

s(3) = 156

s(6) = 216

We need to find the average velocity over the time interval [3,6].

So, average velocity becomes

\dfrac{s(t_1)-s(t_0)}{t_1-t_0}\\\\=\dfrac{s(6)-s(3)}{6-3}\\\\=\dfrac{216-156}{3}\\\\=\dfrac{60}{3}\\\\=20

Hence, the average velocity of the object over the time interval [3,6] is 20.

5 0
2 years ago
What is the circumference of a circle with a radius of 2.5 meters?
Hitman42 [59]

Answer:

15.71m

Step-by-step explanation:

circumference of a circle = 2πr

where r = 2.5m

where π = 3.142

we have,

2*3.142*2.5 = 15.71m

therefore the circumference of a circle with a radius 2.5m = 15.71 m

8 0
3 years ago
Given circle U with diameter ST and radius UQ. QR is tangent to U at Q. If
vfiekz [6]

Answer:

QT = 18

Step-by-step explanation:

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