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dimulka [17.4K]
4 years ago
8

I'm struggling with this one ​

Mathematics
2 answers:
mezya [45]4 years ago
8 0

Answer:

it's the third one cause its square root so x can never be less then 0 but it can go in infinitely

Ede4ka [16]4 years ago
4 0
The third 1111111111111111111111111111111111
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Solve for x. x3 =−125
mafiozo [28]

Answer:

x = -5 or x = 5 (-1)^(1/3) or x = -5 (-1)^(2/3)

Step-by-step explanation:

Solve for x:

x^3 = -125

Taking cube roots gives 5 (-1)^(1/3) times the third roots of unity:

Answer:  x = -5 or x = 5 (-1)^(1/3) or x = -5 (-1)^(2/3)

6 0
4 years ago
What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix? Enter the equation in the box.
antiseptic1488 [7]

Check the picture below.  So the parabola looks more or less like so.

let's recall that the vertex is half-way between the focus point and the directrix, at "p" units away from both.

Let's notice that the focus point is below the directrix, that means the parabola is vertical, namely the squared variable is the "x", and it also means that it's opening downwards as  you see in the picture, namely that "p" is negative, in this case "p" is 1 unit, and thus is -1.

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-2\\ k=5\\ p=-1 \end{cases}\implies 4(-1)(y-5)=[x-(-2)]^2\implies -4(y-5)=(x+2)^2 \\\\\\ y-5=-\cfrac{1}{4}(x+2)^2\implies y=-\cfrac{1}{4}(x+2)^2+5

6 0
3 years ago
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aivan3 [116]

Answer:

a=b

Step-by-step explanation:

4 0
4 years ago
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liq [111]
What was the answer?
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A rectangle has an area of 102 cm2. The length of the rectangle is 17 cm.
densk [106]
102 / 17 = 6 
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34 + 12 = 46  p=46 
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3 years ago
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