Answer:
361/1000
Step-by-step explanation:
this should be the answer
Answer:
We reject H₀
we accept Hₐ seeds in the packet would germinate smaller than 93%
Step-by-step explanation:
Test of proportions
One tail-test (left side)
93 % = 0.93
p₀ = 0,93
1.- Hypothesis
<h3>
H₀ ⇒ null hypothesis p₀ = 0.93</h3><h3>
Hₐ ⇒ Alternative hypothesis p = 0.875</h3><h3>
2.-Confidence interval 95 %</h3><h3>
α = 0,05 </h3><h3>
and </h3><h3>
z(c) = - 1.64</h3><h3>
3.- Compute z(s)</h3><h3>
z(s) = (p - p₀)/√(p₀*q₀)/n z(s) = (0.875-0.93)/√0.93*0.07)200</h3><h3>
z(s) = - 0,055/ √0.0003255</h3><h3>
z(s) = - 0.055/ 0.018</h3><h3>
z(s) = - 3,06</h3><h3>
4.-Compere z(c) and z(s)</h3><h3>
z(s) < z(c) -3.06 < -1.64</h3><h3>
z(s) is in rejection region, we reject H₀</h3>
Answer:
y = 2x - 2
Step-by-step explanation:
hope this helps
