Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Replace f(x) in the equation with what it equals:
Distribute 4 to each term in parentheses:
The answer is
C.
First let's do parentheses. 1*10^-6 = .000001. Now divide that by one it equals the same thing. Now you need to multiply that by 45612.21. That equals 0.04561221μ
You just have to write it down (7.7.7.7.7.7.7=49)
1.09 because all percents are divided by 100 to find the decimal
