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2 years ago

There are 72 squares in the model. 72 squares What is the result of 72 divided by 12? 6 8 9 12

Mathematics

2 answers:

bearhunter [10]2 years ago

8 0

Answer:

Step-by-step explanation:

72 divided by 12 equals 6

Mamont248 [21]2 years ago

6 0

Answer: it is (a)

explanation: in took the test :)

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A bank account pays 4.2% interest.write an equation with an intial value 2000.how much will the account have in it after 5 years

GarryVolchara [31]

Answer:

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Step-by-step explanation:

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2 years ago

What is the slope of the line that passes through the points (-9, -9) −6,−12)?

Fed [463]

Answer:

m = -1

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

Therefore,

slope = (-12-(-9))/(-6-(-9))

= -3/3

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3 years ago

85) A6-foot man casts an 8-foot shadow. How tall is a tree that casts a 20-foot shadow?

vichka [17]

Answer:

15 foot

Step-by-step explanation:

6 foot = 8 foot shadow

3 foot= 4 foot shadow

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please give me brainliest!!!

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3 years ago

Write the expression as a square of a monomial. a 81x^4

poizon [28]

Answer:

(9x²)²

Step-by-step explanation:

Given the expression 81x⁴, to write the expression as a square of a monomial, first we will assign a variable to the expression.

y = 81x⁴

Then we take the square root of both sides of the expression

√y = √81x⁴

y^½ = √81 × √x⁴

y^½ = 9x²

Squaring both sides of the resulting equation to get y back

(y^½)² = (9x²)²

y = (9x²)²

The expression as a square of a monomial is (9x²)²

7 0

3 years ago

Read 2 more answers

AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Gre4nikov [31]

Answer:

Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

$Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds$

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

$\frac{200}{60} = \frac{10}{3} \approx 3.33$ loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

$\frac{200}{65} = \frac{40}{13} \approx 3.08$ loops per minute

then the period is:

$\frac{13}{40} =0.325\,\,\,minutes$

Therefore runner B has the smaller period

8 0

3 years ago