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mr_godi [17]
3 years ago
9

Compare the orbital notations of the substances investigated in this experiment with their attraction to the magnet. What unique

feature in the orbital notation could be used to predict an attraction to a magnet
Chemistry
1 answer:
Alisiya [41]3 years ago
8 0

Answer:

Number of unpaired electrons

Explanation:

We know that for the compounds listed, the nature of the electrons in the d orbitals affects their interaction with an applied magnetic field.

If there are unpaired d electrons present, the compound is paramagnetic and is more strongly attracted to a magnetic field.

Similarly, if there are paired d electrons, the compound is diamagnetic and is less strongly attracted to a magnetic field.

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my digc fell off your mom pu___ssy

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3 years ago
The formula StartFraction actual yield over theoretical yield EndFraction. is used to calculate the ____ yield of a reaction.
Drupady [299]

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Percentage yield

Explanation:

3 0
3 years ago
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What is the OH- concentration of a solution whose pH is 12.40?
Elanso [62]
PH + pOH = pKw = 14

12.40 + pOH = 14

pOH = 14 - 12.40

pOH = 1.6

[OH⁻] = 10 ^{-pOH}

[OH⁻] = 10 ^{-1.6}

[OH⁻] = 2.5x10⁻² M

hope this helps!
7 0
3 years ago
Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodiu
Deffense [45]

Answer:

Density of unit cell ( rhodium) = 12.279 g/cm³

Explanation:

Given that:

The radius (r) of a rhodium atom = 135 pm

The atomic mass of rhodium = 102.90 amu

For a face-centered cubic unit cell,

r = \dfrac{a}{2\sqrt{2}}

where;

a = edge length.

Making "a" the subject of the formula:

a = 2 \sqrt{2} \times r

a = 2 \times 1.414 \times 135 \ pm

a = 381.8 pm

to cm, we get:

a = 381.8 × 10⁻¹⁰ cm

However, recall that:

density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}

where;

mass of unit cell = mass of atom × numbers of atoms per unit cell

Also;

mass\  of\ atom =\dfrac{ atomic \ mass}{Avogadro  \  number}

mass\  of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}

Recall also that number of atoms in a unit cell for a  face-centered cubic = 4

So;

mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4

mass of unit cell = 6.83380375 × 10⁻²² g

Density  \ of  \ unit \  cell = \dfrac{6.83380375 \times 10^{-22}}{(381.8\times 10^{-10})^3}

Density of unit cell ( rhodium) = 12.279 g/cm³

3 0
3 years ago
Plasma is the most common state of matter in the?
Paladinen [302]

Answer:

Universe

Hope its helpful

Thank you

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