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1 year ago

If 5.00 L of argon gas is at 0.460 atm and -123°C, what is the volume at STP?

Chemistry

1 answer:

Sergio039 [100]1 year ago

3 0

Answer:

4.27 L

Explanation:

STP = 0 C and 1 atm

P1V1/T1 = P2V2/T2 where T is in Kelvin

P1 V1 / T1 *T2/P2 = V2

.469 * 5 / ( 273.15-123) * 273.15/1 = V2 = 4.27 L

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Frozen water is less dense than liquid water, allowing lake organisms to survive winter.

klasskru [66]

True.

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7 0

3 years ago

Read 2 more answers

Can someone plz explain ionic and covalent bonding plzzzz!!!

Alexeev081 [22]

Answer:

Ionic Bonding: The formation of an Ionic bond is the result of the transfer of one or more electrons from a metal onto a non-metal.

Covalent Bonding: Bonding between non-metals consists of two electrons shared between two atoms.

Explanation:

4 0

2 years ago

The crystallization of salt from evaporating seawater a. is an example of precipitation from a solution. b. is, in mineralogic t

Ad libitum [116K]

Answer:

is an example of precipitation from a solution.

Explanation:

3 0

3 years ago

How many grams of CuF2 are needed to make a 2.8 M solution

11111nata11111 [884]

Molarity is given as,

Molarity = Moles / Volume of Solution ----- (1)

Also, Moles is given as,

Moles = Mass / M.mass

Substituting value of moles in eq. 1,

Molarity = Mass / M.mass × Volume

Solving for Mass,

Mass = Molarity × M.mass × Volume ---- (2)

Data Given;

Molarity = 2.8 mol.L⁻¹

M.mass = 101.5 g.mol⁻¹

Volume = 1 L (I have assumed it because it is not given)

Putting values in eq. 2,

Mass = 2.8 mol.L⁻¹ × 101.5 g.mol⁻¹ × 1 L

Mass = 284.2 g of CuF₂

5 0

2 years ago

A radioisotope decays to give an alpha particle andPb-208.

oee [108]

Answer: The original element is $_{84}^{212}\textrm{Po}$

Explanation:

Alpha decay is defined as the process in which alpha particle is emitted. In this process, a heavier nuclei decays into a lighter nuclei. The alpha particle released carries a charge of +2 units.

The released alpha particle is also known as helium nucleus.

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha$

For the given alpha decay process of an isotope:

$^{Z}_{A}\textrm{X}\rightarrow ^{208}_{82}\textrm{Pb}+_2^4\alpha$

To calculate A:

Total mass on reactant side = total mass on product side

A = 208 + 4

A = 212

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

Z = 82 + 2

Z = 84

The isotopic symbol of unknown element is $_{84}^{212}\textrm{Po}$

Hence, the original element is $_{84}^{212}\textrm{Po}$

3 0

3 years ago