If 5.00 L of argon gas is at 0.460 atm and -123°C, what is the volume at STP?

1 answer:

3 0

Answer:

4.27 L

Explanation:

STP = 0 C and 1 atm

P1V1/T1 = P2V2/T2 where T is in Kelvin

P1 V1 / T1 *T2/P2 = V2

.469 * 5 / ( 273.15-123) * 273.15/1 = V2 = 4.27 L

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