Answer:
See explanation
Explanation:
The first step in this reaction is a unimolecular reaction. It involves the formation of the carbocation. This is so because tertiary alkyl halides only undergo substitution by SN1 mechanism due to sterric crowding.
The second step in the reaction is bi molecular. In this step, the carbocation now combines with the OH^- to yield the alcohol.
Net equation of the reaction is;
(CH3)3CBr + OH^- -------> (CH3)3COH + Br^-
The intermediate here is the carbocation, (CH3)3C^+
Answer:
There are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.
Explanation:
We can calculate the number of moles (η) of BeO as follows:
Where:
m: is the mass = 250 g
M: is the molar mass = 25.0116 g/mol
Hence, the number of moles is:
Therefore, there are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.
I hope it helps you!
[B][C] / [A]^2
Products raised to the coefficients over reactants raised to the coefficients
Answer:
polypeddite chain I guess
