1.
g > 6.4
<h3>Answer: A. 7 > 6.4</h3>
2.
y + 2 > 8 <em>subtract 2 from both sides</em>
y > 6
<h3>Answer: D. 7 > 6</h3>
3.
6 > z(10 - z)
A. z = 0 → 6 > 0(10 - 0) → 6 > 0 CORRECT
B. z = 1 → 6 > 1(10 - 1) → 6 > 1(9) → 6 > 9 FALSE
C. z = 2 → 6 > 2(10 - 2) → 6 > 2(8) → 6 > 16 FALSE
D. z = 3 → 6 > 3(10 - 3) → 6 > 3(7) → 6 > 21 FALSE
<h3>Answer: A. 0</h3>
4.
The list of factors of 24:
1, 24, 2, 12, 3, 8, 4, 6
<h3>Answer: D. {1, 2, 3, 4, 6, 8, 12, 24}</h3>
Answer:
16 = l
4 = w
Step-by-step explanation:
{64 = wl
{40 = 2w + 2l
{l = 8 + 2w
64 = w[8 + 2w] ↷
-64 + 8w + 2w² ↷
[2w² - 8w] + [16w - 64]
2w[w - 4] 16[w - 4]
[w - 4][2w + 16] = 0
↑
This is the expression we want because when we talk about dimensions, we want NON-NEGATIVE numbers. The other expression results in -8 = w, and we do not want that; this expression gives us a solution of 4 = w, and THIS is exactly what we want. Anyway, you plug "4" back into the system of equations and you will get a length of 16 centimetres.
I am joyous to assist you anytime.
Answer:
7/15
Step-by-step explanation:
Answer:
C) 65 miles per hour
Step-by-step explanation:
715 divided by 11
<u>Answer</u>-
<em>The total capacitive reactance of the circuit is </em><em>7.96 Ω.</em>
<u>Solution-</u>
Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.
The effective/equivalent capacitance of the circuit is,
As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.
We know that,
Where,
= Capacitive Reactance (in Ω)
f = frequency (in Hz)
C = Capacitance (in F)
Here given,
= ??
f = 400 Hz
C = 50 mF = 
F
Putting the values in the formula,
Therefore, the total capacitive reactance of the circuit is 7.96 Ω.
