Can yall help did i do this correctly <br> PLEASE HELP

A spinner has 4 equal sections. after 12 spins, the spinner landed on section a 4 times, section b 5 times, section c 2 times, a

Eduardwww [97]

Answer:

The Experimental Probability of the spinner stopping on Section A is 1/3.

Step-by-step explanation:

Number of time spinner landed on section A = 4

Number of time spinner landed on section B = 5

Number of time spinner landed on section C = 2

Number of time spinner landed on section D = 1

Total Number of spins = 12

$Probability=\frac{Number\:of\;Favorable\:outcome}{Number\:of\:total\;outcome}=\frac{4}{12}=\frac{1}{3}$

Therefore, The Experimental Probability of the spinner stopping on Section A is 1/3.

6 0

3 years ago

How many times can 256 go into 495

ddd [48]

Answer:

once

Step-by-step explanation:

8 0

3 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

22. MULTIPLE CHOICE What number is 0.02% of 50? (Skills Review Handbook) (A) 0.01 (B) 0.1 (C) 1 (D) 100

emmainna [20.7K]

Answer:

$x = 1$

Then the answer is C

Step-by-step explanation:

1) Set a linear equation

$\frac{2}{100} = \frac{x}{50}$

2) Cross multiply

$100x = 2 \times 50$

3) Multiple the right side

$100x = 100$

4) Divide both side by 2

$\frac{100x}{100} = \frac{100}{100}$

5) Solving the linear equation

$x = 1$

The answer is (C)

7 0

3 years ago

(a+8)^2-(b+5)^2 solve with suitable identity

Katen [24]

Step-by-step explanation:

eliminăm parantezele:

a²+16a+64-(12b+60)

calculăm:

a²+16a+64-12b-60

Rezultatul:

a²+16a+4-12b

8 0

3 years ago

Can yall help did i do this correctly PLEASE HELP