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777dan777 [17]
3 years ago
14

What is the mean of the data set below 2, 3, 5, 6, 6, 10, 15, 15,

Mathematics
1 answer:
SpyIntel [72]3 years ago
4 0
6.5 is the mean of the data
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If you add 12 to my number and then multiply the result by 3, you will get 64 more than two-thirds of my number. Find my number.
anastassius [24]

Answer:

The number is 12

Step-by-step explanation:

[] First, let's turn all these words into something mathematical. N will equal "my number"

-><u> If you add 12 to my number</u> and then multiply the result by 3, you will get 64 more than two-thirds of my number.

-> n + 12 <u>and then multiply the result by 3</u>, you will get 64 more than two-thirds of my number.

-> 3(n + 12), you will get 64 more than <u>two-thirds of my number</u>.

-> 3(n + 12) = <u>64 more than</u> \frac{2n}{3}

-> 3(n + 12) = 64 +  \frac{2n}{3}

[] Phew, okay. Now it is something we can solve and less scary;

[Given]

3(n + 12) = 64 +  \frac{2n}{3}

[Distribute]

3n + 36 = 64 +  \frac{2n}{3}

[Multiply both sides by 3]

9n + 108 = 192 + 2n

[Subtract 108 and 2n from both sides]

7n = 84

[Divide both sides by 4]

n = 12

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

8 0
3 years ago
What is the solution to the following system?
andrezito [222]

Answer:

l think the problem of the is your work is not of the number l got.

x=2

8 0
2 years ago
(9x+4) what is the answer hurry taking a test
igor_vitrenko [27]

Answer:

9x+4

Step-by-step explanation:

remove the parentheses

8 0
3 years ago
Read 2 more answers
A sample of radium has a weight of 1.5 mg and a half-life of approximately 6 years.
pogonyaev

Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

5 0
2 years ago
Transform the equation to isolate x: ax=bx+1. How is the value of x related to the difference of a and b
nasty-shy [4]

Answer:

x is the reciprocal of the difference of a and b.

Step-by-step explanation:

ax=bx+1

Subtract by bx on both sides

ax-bx=1

x(a-b)=1

x= 1/(a-b)

8 0
2 years ago
Read 2 more answers
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