All categories

3 years ago

What are the solutions of the equation (5x − 2)(x + 6) = 0?

Mathematics

1 answer:

Mrrafil [7]3 years ago

4 0

Answer:

A. 0.4 , -6

Step-by-step explanation:

equate each of them to 0

5x - 2 =0 , x + 6 = 0

5x = 2 , x = 0 - 6

x = 2/5 , x = -6

x = 0.4 , x = -6

You might be interested in

What is the answer to 20=5x 10y?

My name is Ann [436]

I hope this helps you 5x=20 x=4 10x=10×4=40

5 0

3 years ago

78 divided by 21?:-:

MA_775_DIABLO [31]

Answer:

3.7 or 3.71428571429

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the value of an investment of $650 invested at an annual interest rate of 1.5% compounded monthly for 16 years?

diamong [38]

Answer:

it should be 650

1.5

0.015

Step-by-step explanation:

6 0

3 years ago

Estimate the area of Alberta in square miles. Show your reasoning

ella [17]

Answer: About $278,250\ mi^2$

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid can be calcualted with the formula:

$A_t=\frac{h}{2}(B+b)$

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

$A_r=lw$

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

$A=\frac{h}{2}(B+b)+lw$

Substituting vallues, you get:

$A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2$

Therefore, the area of of Alberta is about $278,250\ mi^2$ .

5 0

3 years ago

Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long

Ne4ueva [31]

We are given

Jim's backyard:

Length is

$L=15\frac{5}{6} =\frac{95}{6} yards$

width is

$W=10\frac{2}{5} =\frac{52}{5} yards$

Since, this is rectangle

so, we can find area of rectangle

$A=L*W$

$A=(\frac{95}{6})*(\frac{52}{5})$

$A=\frac{494}{3} yard^2$

Area of one sod:

length is

$l=1\frac{1}{3} =\frac{4}{3} yards$

width is

$w=1\frac{1}{3} =\frac{4}{3} yards$

Since, it is rectangle in shape

so,

$Area=l*w$

$A=\frac{4}{3}*\frac{4}{3}$

$A=\frac{16}{9}yard^2$

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

$N=\frac{\frac{494}{3} }{\frac{16}{9} }$

now, we can simplify it

$N=\frac{741}{8}$ pieces need ..............Answer

7 0

4 years ago