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il63 [147K]
3 years ago
5

Hey does anyone think nervegear would be possible? (Just asking)

Computers and Technology
2 answers:
Vlada [557]3 years ago
7 0

Answer:

Depends

Explanation:

Technology is not advanced yet, so building a fully functional nerve gear is difficult. It could be possible in a few years though.

swat323 years ago
5 0

Answer:

No, the Nerve Gear cannot be possible at the moment. However, in Japan, they are creating the Nerve Gear and is to be released in May 2022 told by the creator, Kayaba Akihiko. So, the Nerve Gear cannot be possible in 2020 but in 2022. We just have to wait for two more years.

Explanation:

please choose me as brainliest if that is ok ;)

You might be interested in
someone who protects valuable online information, like phone numbers and passwords would be considered​
charle [14.2K]

Answer: i believe a digital citizen

i am not 100% sure about that answer but i reaserached a little and thats what i found :)

I hope this helps u out a little a thank and a brainlist would be greatly appreciatecd :)

6 0
3 years ago
A mobile device user has entered her user ID and password to access an online account. The user immediately receives a text mess
tensa zangetsu [6.8K]

Answer:

A. Multifactor authentication

Explanation:

Multifactor authentication is a security system process that requires a user to verify his or her identity by providing two categories of credentials.

A mobile device user has entered her user ID and password to access an online account, she immediately receives a text message with a unique PIN or One Time Password (OTP) that must be entered before she is granted access to the account. This is an example of a multifactor authentication security method.

8 0
3 years ago
)In a vector implementation of a stack ADT, you add an entry to the top of a stack using which vector method?
kotykmax [81]

Answer:

B.add.

Explanation:

boolean add(element)

The add method in java inserts an element in the vector.It's return type is Boolean it returns true if the element is successfully inserted in the vector and false if the operation is unsuccessful.There is no Push operation in vector.Hence we conclude that the answer is add.

8 0
3 years ago
1. Add the following method to the Point class:
Pachacha [2.7K]

Answer:

Explanation:

The following code is written in Java and creates all of the methods that were requested in the question. There is no main method in any of these classes so they will have to be called from the main method and call one of the objects created method for the code to be tested. (I have tested it and it is working perfectly.)

class Point {

   private int x, y;

   public void Point(int x, int y) {

       this.x = x;

       this.y = y;

   }

   public double distance (Point other) {

      double distance = Math.sqrt(Math.pow((other.x - this.x), 2) + Math.pow((other.y - this.y), 2));

      return distance;

   }

   

   public int quadrant() {

       if (this.x > 0 && this.y > 0) {

           return 1;

       } else if (this.x < 0 && this.y > 0) {

           return 2;

       } else if (this.x < 0 && this.y < 0) {

           return 3;

       } else if (this.x > 0 && this.y < 0) {

           return 4;

       } else {

           return 0;

       }

   }

}

class Name {

   String firstName, lastName;

   char middleInitial;

   

   public String getNormalOrder() {

       String fullName = firstName + " " + middleInitial + " " + lastName;

       return fullName;

   }

   

   public String getReverseOrder() {

       String fullName = lastName + ", " + firstName + " " + middleInitial;

       return fullName;

   }

}

4 0
2 years ago
Two numbers are given (numbers are entered from the keyboard). If both numbers are positive, then output their sum, if both numb
AleksAgata [21]

Answer:

The program in Python is as follows:

num1 = int(input())

num2 = int(input())

if num1 >=0 and num2 >= 0:

   print(num1+num2)

elif num1 <0 and num2 < 0:

   print(num1*num2)

else:

   if num1>=0:

       print(num1**2)

   else:

       print(num2**2)

Explanation:

This gets input for both numbers

num1 = int(input())

num2 = int(input())

If both are positive, the sum is calculated and printed

<em>if num1 >=0 and num2 >= 0:</em>

<em>    print(num1+num2)</em>

If both are negative, the products is calculated and printed

<em>elif num1 <0 and num2 < 0:</em>

<em>    print(num1*num2)</em>

If only one of them is positive

else:

Calculate and print the square of num1 if positive

<em>    if num1>=0:</em>

<em>        print(num1**2)</em>

Calculate and print the square of num2 if positive

<em>    else:</em>

<em>        print(num2**2)</em>

3 0
2 years ago
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